Speed control of DC and AC machines Lab Report Example | Topics and Well Written Essays - 2500 words

Speed control of DC and AC machines - Lab Report ExampleSteady-state conditions are to be used in the case where the DC get needs to be excited separately. Loading conditions should be varied and tested. The rectifiers available include the single-phase half controlled bridge rectifier containing a flywheel diode. Cases of firing angle in the apparatus that is used above ought to be set to a fixed value.Voltage and resistance variation affect characteristics of the armature while flux regarding the pole affects magnetic properties of the labor. It sets the establish for the speed control methods as armature control method and the field control methods.Resistance variation is achieved via connecting an external resistance with the voltage supply to the motor armature. losings being negligible are ignored. Alternatively speed control can be achieved by a rheostat resistance in series with the armature of the motor. magnetic properties of the motor can be varied using a field divert er method. Armature control method has superiority compared to the other methods because it has the abilities to offer fine control of the motor speed, a unified acceleration, and the regulation properties accompanying speed control are superior. On the contrary, the method requires standardized patterns that increases the cost and delivers low efficiency when carrying lighter loads.The circuit, as stated above, is made up of controlled and the uncontrolled rectifiers. Diode as components of the design and the freewheeling operations occurs regardless of allowing a forbid voltage output. Clamping at energy does not guarantee the rectification of negative voltage hence a half controlled. The positive voltage levels are made use via the rectifier while the negative voltages are cut-off hence unnecessary.The setup is composed of diodes and the SCRs. With Vin being positive, triggering of SCR S1 occurs at the firing angle determined and denoted as a. current flow will begin from SCR S 1 and thus flow through